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        {
            "lemma": "ἀρτιάζω",
            "meanings": 1,
            "language": "grc",
            "descriptions": [
                {
                    "dictionary": "Bailly",
                    "reference": "Bailly 2020 Hugo Chávez Gérard Gréco, André Charbonnet, Mark De Wilde, Bernard Maréchal & contributeurs \/ Licence Creative Commons Attribution - Pas d'Utilisation Commerciale - Pas de Modification — « CC BY-NC-ND 4.0 »",
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                    "description": "<font color='darkgreen'>(<i>seul. prés., impf<\/i>. ἠρτίαζον, <i>ao<\/i>. ἠρτίασα) :<\/font><br\/><b>      1<\/b> jouer à pair ou impair, AR. <i>Pl. 816 ;<\/i> PLAT. <i>Lys. 206<\/i> e ;<br\/><b>      2<\/b> compter, ANTH. <i>12, 145<\/i>.<p style='color:darkblue'><b>Étym<\/b>. ἄρτιος.<\/p>"
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                {
                    "dictionary": "LSJ",
                    "reference": "Liddell-Scott-Jones, Greek-English Lexicon (9th ed., 1940)",
                    "source": null,
                    "description": "(&lt; ἄρτιος) <b>play at odd and even<\/b>, Ar. <i>Pl.<\/i> 816; ἀστραγάλοις ἀ. Pl. <i>Ly.<\/i> 206e, prob. in Arist. <i>Div. Somn.<\/i> 463b20.<br\/><b>count<\/b>, <i>AP<\/i> 12.145."
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                    "dictionary": "Pape",
                    "reference": "Pape, Griechisch-deutsches Handwörterbuch (3. Aufl., 1914)",
                    "source": null,
                    "description": "<b>1)<\/b> <i>gerade oder ungerade spielen<\/i>, Ar. <i>Plut<\/i>. 816 ; Plat. <i>Lys<\/i>. 206e ; Xen. <i>Hipparch<\/i>. 5.10.<br\/><b>2)<\/b> <i>genau angeben, zählen<\/i>, ψεκάδα ἀριθμητήν <i>Ep.adesp<\/i>. 34 (XII.145)."
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